What is the voltage into the second amplifier in cascade if each amplifier draws 1.5 amps and the loop resistance is 1.38 ohms?

To determine the voltage into the second amplifier in cascade, it’s crucial to apply Ohm’s law, which states that voltage (V) is equal to the current (I) multiplied by the resistance (R). In this case, each amplifier draws a current of 1.5 amps, and the loop resistance is 1.38 ohms.

First, calculate the voltage drop across the loop resistance using the formula:

Voltage drop (V_drop) = Current (I) × Resistance (R)

= 1.5 amps × 1.38 ohms

= 2.07 volts.

Next, consider the input voltage feeding the first amplifier. Assuming the input voltage is sufficient to overcome the drop for both amplifiers, the output voltage level from the first amplifier will have a voltage drop that needs to be accounted for when considering the voltage entering the second amplifier.

If we start with a system setup where a specific voltage is applied (let’s assume it's the standard or maximum operational voltage of 90 VAC for the initial calculations) and apply the voltage drop across the resistance due to the current drawn:

Input voltage to the second amplifier = Voltage source - Voltage drop

= 90 VAC - (2.07 volts